This Article consist of most important ” Allegation or Mixture Questions and Answers ” topic that are mostly asked in all competitive exams. We collected these questions from the students who appeared in exams. Now try to solve these questions.

## Allegation or Mixture Questions and Answers

**Question : 1** In what ratio must a grocer mix two varieties of pulses costing Rs. 15 and Rs. 20 per kg respectively so as to get a mixture worth Rs. 16.50 kg?

A. 3 : 7

B. 5 : 7

C. 7 : 5

D. 7 : 3

**Show Answer**

**Correct Answer : ** **C**

**Explanation : **

By the rule of alligation:

Cost of 1 kg pulses of 1st kindCost of 1 kg pulses of 2nd kind

Rs. 15 Mean Price

Rs. 16.50 Rs. 20

3.50 1.50

Required rate = 3.50 : 1.50 = 7 : 3

**Question : 2** Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:

A. Rs. 169.50

B. Rs. 170

C. Rs. 175.50

D. Rs. 180

**Show Answer**

**Correct Answer : ** **B**

**Explanation : **

Since first and second varieties are mixed in equal proportions.

So, their average price = Rs. 126 + 135 = Rs. 130.50

2

So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.

By the rule of alligation, we have:

Cost of 1 kg of 1st kind + Cost of 1 kg tea of 2nd kind = cost of 1 kg of total mixture

(Rs. 130.50 Mean Price + Rs. X) / 2 = Rs. 153

130.50 + X = 153 * 2 , 130.50 + X = 306

X = 306 – 130.50 = **175.50 **

**Question : 3** A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?

A. 1/3|

B. 1/4

C. 1/5

D. 1/7

**Correct Answer : C**

**Explanation : **

Suppose the vessel initially contains 8 litres of liquid.

Let x litres of this liquid be replaced with water.

Quantity of water in new mixture = ( 3- 3x/8 + x ) litres

Quantity of syrup in new mixture = 5 – 5x litres

8

3 – 3x + x = 5 – 5x

8 8

5x + 24 = 40 – 5x

10x = 16

x = 8 .

5

So, part of the mixture replaced = 8 x 1 = 1 .

5 8 5

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