Allegation or Mixture Questions and Answers

This Article consist of most important ” Allegation or Mixture Questions and Answers ” topic that are mostly asked in all competitive exams. We collected these questions from the students who appeared in exams. Now try to solve these questions.

Allegation or Mixture Questions and Answers

 

Question : 1    In what ratio must a grocer mix two varieties of pulses costing Rs. 15 and Rs. 20 per kg respectively so as to get a mixture worth Rs. 16.50 kg?

A. 3 : 7
B. 5 : 7
C. 7 : 5
D. 7 : 3

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Correct Answer :   C
Explanation :
By the rule of alligation:

Cost of 1 kg pulses of 1st kindCost of 1 kg pulses of 2nd kind
Rs. 15 Mean Price
Rs. 16.50 Rs. 20
3.50 1.50
Required rate = 3.50 : 1.50 = 7 : 3

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Question : 2    Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:

A. Rs. 169.50
B. Rs. 170
C. Rs. 175.50
D. Rs. 180

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Correct Answer :  B
Explanation :
Since first and second varieties are mixed in equal proportions.

So, their average price = Rs. 126 + 135 = Rs. 130.50
2
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.

By the rule of alligation, we have:

Cost of 1 kg of 1st kind + Cost of 1 kg tea of 2nd kind = cost of 1 kg of total mixture

(Rs. 130.50 Mean Price + Rs. X) / 2  = Rs. 153

130.50 + X = 153 * 2  , 130.50 + X = 306

X = 306  – 130.50 = 175.50 

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Question : 3   A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?

A. 1/3|
B. 1/4
C. 1/5
D. 1/7

Correct Answer : C
Explanation :
Suppose the vessel initially contains 8 litres of liquid.

Let x litres of this liquid be replaced with water.

Quantity of water in new mixture = ( 3- 3x/8 + x ) litres
Quantity of syrup in new mixture = 5 – 5x litres
8
3 – 3x + x = 5 – 5x
8 8
5x + 24 = 40 – 5x

10x = 16

x = 8 .
5
So, part of the mixture replaced = 8 x 1 = 1 .
5 8 5

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