Square Root and Cube Root Problems

This Article consist of most important ” Square Root and Cube Root Problems ” that are mostly asked in all competitive exams. We collected these questions from the students who appeared in exams. Now try to solve these questions.

Square Root and Cube Root Problems

 

Question : 1    The square root of 64009 is:

A. 253
B. 347
C. 363
D. 803

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Correct Answer :   D
Explanation :
2|64009( 253
|4
|———-
45|240
|225
|———-
503| 1509
| 1509
|———-
| X
|———-
64009 = 253

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Question : 2    How many two-digit numbers satisfy this property.: The last digit (unit’s digit) of the square of the two-digit number is 8 ?

A. 1
B. 2
C. 3
D. None of these

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Correct Answer :   D
Explanation :
A number ending in 8 can never be a perfect square.

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Question : 3    A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 59.29, the number of the member is the group is:

A. 57
B. 67
C. 77
D. 87

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Correct Answer :   C
Explanation :
Money collected = (59.29 x 100) paise = 5929 paise.

Number of members = square root of (5929) = 77

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Question : 4    square root of 1.5625 = ?

A. 1.05
B. 1.25
C. 1.45
D. 1.55

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Correct Answer :   B
Explanation :
1|1.5625( 1.25
|1
|——-
22| 56
| 44
|——-
245| 1225
| 1225
|——-
| X
|——-
1.5625 = 1.25

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Question : 5    The least perfect square, which is divisible by each of 21, 36 and 66 is:

A. 213444
B. 214344
C. 214434
D. 231444

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Correct Answer :   A
Explanation :
L.C.M. of 21, 36, 66 = 2772.

Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11

To make it a perfect square, it must be multiplied by 7 x 11.

So, required number = 2sq x 3sq x 7sq x 11sq = 213444

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