Speed enhancement and Tricks to solve aptitude questions
Quantitative is the crucial subject for all the competitive exams. Solving good percentage of questions in minimum time leads to the win win situation. At a first glance to a Quantitative questions it seems that we know the solutions to the most of them but the biggest factor that restrict us in solving all the questions correctly is Time , yes time is one of the most crucial factor of all competitive exams . Look at the crucial government exams like SSC CGL , PO exams , Bank exams , LIC and other good examinations every minute matters . If we are good with our preparations and covered all the important topic still cracking the exams becomes tough why ? Yes in the post will eliminate this concern and will help you to sure shot crack these examinations .
We will help you with the tricks to enhance you calculation speeds which is very much required in a Quantitative questions. Quantitative questions are most time consuming in any competitive exams . Solving maximum of them in minimum time guarantees in cracking the exam and final selections .
Let’s begin with quick,easy and most wanted tricks to solve aptitude questions for calculations .
- Learn squares up to 25 which is required in many questions to avoid calculations .
- Learn cubes up to 12
- Learn power of 2 up to 12
- Learn power of 3 up to 6
Some ways of simplifying calculations and to carry big calculations in seconds
- For multiplications by 5 . Try multiply by 10 and divide by 2 which is quick .
Example –
6457 * 5 = [ 6457 * 10 = 64570 ==> 64570/2 = 32185 ]
This will save 5 to 10 seconds . You will have to perform this at number of places which will save 4 to 5 mins and you can solve more 4 -5 questions in that time which will improve the chances of selection .
Multiplications Tricks to solve aptitude questions
- For multiplications by 25 . Try multiply by 100 and divide by 4 which is quick .
- For multiplications by 125 . Try multiply by 1000 and divide by 8 which is quick.
- For multiply by 12 , the rule is double the digit and add the right hand digit to it , write the result and the carry forward to the subsequent step for multiplication .
Example –
7469 * 12
Step 1 – consider 0 both ends for simplification like 0|7469|0
Step 2 – double the digit 9 ie 18 and add the right digit 0 to it write the result 8 and the carry forward 1 to next step
18+0 = 18 write 8 and take 1 to next step
Step 3 – double the digit 6 ie 12 and add right hand digit 9 and the carry forward 1 from previous step so result is 22 write 2 and the carry forward in this to next step
12+9+1 =22 write 2 and take 2 to next step
Result from above steps so far is 28
Step 4 – double the digit 4 and add right hand digit 6 and carry forward from previous step is 2 result is
8+6+2 = 16 write 6 and take 1 to next step
Result from above steps so far is 628
Step 5 – double the digit 7 and add right hand digit 4 and carry forwad 1
14+4+1 = 19 write 9 and take 1 to next step
Result so far 9628.
Step 6 – double 0 add 7 and 1 from previous step
0+7+1 = 8
Final result is 89628 .
- Multiplication by 19 can be treated as (20 -1)
like 12345 * 19 = 12345 (20 -1 ) = 12345*20 – 12345 = 234555
Calculations of squares tricks to solve aptitude questions
- Getting the square of number ending with 5 is very simple like
252 = 2*3 and 25 in last = 625
352 = 3 *4 and 25 in last = 1225
452 = 4*5 and 25 in last = 2025
552 = 5*6 and 25 in last = 3025
and so on……
How to find other squares quickly –
Now for 262 we can easily find it by 252
Like 262 = 252 + 26th odd no.
Nth odd no = (2n -1)
26th odd no = 2*26 -1 = 61
262 = 252 +26th odd no
=625 +61 = 676
Example – 312 = 302 + 31 odd no = 900 + 61 = 961
Like this way we see how to find the squares of numbers 1 more than those whose squares we know
Now will see for squares of no 1 less than those whose squares we know
Example
292 = 302 – 30th odd no = 900 – 59 = 841
342 = 352 – 35th odd no = 1225 – 69 = 1156
742 = 752 – 75th odd no = 5625 – 149 = 5476
Now to find squares of no which the 2 more than those whose squares we know
Example
972 = 952 + 4* 96 = 9025 + 384 = 9409
772 = 752 + 4*76 = 5625 +304 = 5929
Now to find squares of no which the 2 less than those whose squares we know
532 = 552 – 4*54 = 3025 – 216 = 2809
Summary –
Nth odd no = (2n -1)
902 = 8100
912 = 902 + 91th odd no = 8100 + 181 = 8281
922 = 902 + 4 * 91 = 8100 + 364 = 8464
932 = 952 – 4* 94 = 9025 – 376 = 8649
942 = 952 – 95th odd no = 9025 – 189 = 8836
952 = 9*10 and 25 in last = 9025
Hope you find this arctile based on quick and easy mathematics tricks to solve aptitude questions.